如何将ac字符串转换为c中的转义版本？

#include <stdio.h>
#include <string.h>

void escapeString(const char* ac, char* c) {
    int len = strlen(ac);
    int j = 0;

    for (int i = 0; i < len; i++) {
        switch (ac[i]) {
            case '\"':
                c[j++] = '\\';
                c[j++] = '\"';
                break;
            case '\'':
                c[j++] = '\\';
                c[j++] = '\'';
                break;
            case '\\':
                c[j++] = '\\';
                c[j++] = '\\';
                break;
            case '\n':
                c[j++] = '\\';
                c[j++] = 'n';
                break;
            case '\r':
                c[j++] = '\\';
                c[j++] = 'r';
                break;
            case '\t':
                c[j++] = '\\';
                c[j++] = 't';
                break;
            default:
                c[j++] = ac[i];
                break;
        }
    }

    c[j] = '\0';
}

int main() {
    const char* ac = "Hello, \"World\"!\n";
    char c[100];

    escapeString(ac, c);

    printf("转义后的字符串：%s\n", c);

    return 0;
}