如何将ostringstream十六进制字符串字符对转换为单个unit8_t等效二进制值

#include <iostream>
#include <sstream>
#include <string>
#include <vector>

int main() {
    std::ostringstream oss;
    oss << "A1B2C3D4";  // 假设ostringstream对象中包含的十六进制字符串字符对

    std::string hexString = oss.str();  // 提取字符串内容
    std::vector<uint8_t> binaryValues;  // 存储转换后的二进制值

    for (size_t i = 0; i < hexString.length(); i += 2) {
        std::string hexPair = hexString.substr(i, 2);  // 截取两个字符
        int decimalValue = std::stoi(hexPair, nullptr, 16);  // 转换为十进制整数
        uint8_t binaryValue = static_cast<uint8_t>(decimalValue);  // 强制转换为uint8_t类型
        binaryValues.push_back(binaryValue);  // 存储二进制值
    }

    // 输出转换后的二进制值
    for (const auto& value : binaryValues) {
        std::cout << static_cast<int>(value) << " ";
    }
    std::cout << std::endl;

    return 0;
}