如何按大小对从GetFiles/ GetDirectories检索到的两个文件/文件夹进行排序

import os

def get_file_size(file_path):
    return os.path.getsize(file_path)

def sort_files_by_size(directory):
    files = [os.path.join(directory, f) for f in os.listdir(directory) if os.path.isfile(os.path.join(directory, f))]
    files.sort(key=get_file_size)
    return files

def sort_directories_by_size(directory):
    directories = [os.path.join(directory, d) for d in os.listdir(directory) if os.path.isdir(os.path.join(directory, d))]
    directories.sort(key=get_directory_size)
    return directories

# 示例用法
sorted_files = sort_files_by_size('/path/to/directory')
sorted_directories = sort_directories_by_size('/path/to/directory')