如何按频率而不是字母顺序对字符串数组进行排序

import collections

def frequencySort(strs):
    # 统计每个字符串的频率
    freq = collections.Counter(strs)

    # 自定义比较函数
    def compare(x, y):
        if freq[x] == freq[y]:
            return 1 if x > y else -1
        return freq[x] - freq[y]

    # 根据频率和字母顺序排序
    sorted_strs = sorted(strs, key=lambda x: compare(x, x))

    return sorted_strs

# 示例输入
strs = ["apple", "banana", "apple", "cherry", "banana", "apple"]
# 按频率而不是字母顺序排序
sorted_strs = frequencySort(strs)
print(sorted_strs)