如何旋转比屏幕更大的图像，而不会在颤动中剪切掉溢出的图像？

from PIL import Image

def rotate_image(image_path, angle):
    # 打开图像
    img = Image.open(image_path)
    
    # 计算旋转后的边界框
    img_width, img_height = img.size
    angle_rad = angle * (3.14159 / 180)
    new_width = int(abs(img_width * abs(3.14159 / 2 - angle_rad)) + abs(img_height * abs(angle_rad)))
    new_height = int(abs(img_height * abs(3.14159 / 2 - angle_rad)) + abs(img_width * abs(angle_rad)))
    
    # 创建新的画布
    new_img = Image.new('RGB', (new_width, new_height), (255, 255, 255))
    
    # 旋转图像并粘贴到新画布上
    rotated_img = img.rotate(angle, expand=True)
    new_img.paste(rotated_img, ((new_width - img_width) // 2, (new_height - img_height) // 2))
    
    # 裁剪和缩放以适应屏幕
    screen_width, screen_height = 1920, 1080  # 假设屏幕大小为1920x1080
    resized_img = new_img.resize((screen_width, screen_height), Image.ANTIALIAS)
    
    return resized_img

# 示例使用
rotated_image = rotate_image('path_to_your_image.jpg', 45)
rotated_image.show()