如何有效地将列名转换为(column name -> list of column values)的映射

# 假设数据表的列名存储在列表 column_names 中，数据存储在二维列表 data 中

column_names = ['name', 'age', 'gender']
data = [['John', 25, 'Male'], ['Jane', 30, 'Female'], ['Tom', 28, 'Male']]

column_map = {}  # 创建空的映射

for row in data:
    for i, value in enumerate(row):
        column_name = column_names[i]
        if column_name not in column_map:
            column_map[column_name] = []  # 如果映射中不存在该列名的键，则创建一个空列表
        column_map[column_name].append(value)  # 将列值添加到对应键的值列表中

print(column_map)

{
  'name': ['John', 'Jane', 'Tom'],
  'age': [25, 30, 28],
  'gender': ['Male', 'Female', 'Male']
}