如何根据函数和参数类型获得julia代码的表达式？

function add(x::Int, y::Int)
    return x + y
end

@code_lowered add(2, 3)

CodeInfo(
1 ─ %1 = (Base.add_int)(x, y)
└──      return %1
)

function add(x::Int, y::Int)
    return x + y
end

@code_typed add(2, 3)

CodeInfo(
1 ─ %1 = x + y
└──      return %1
)

function add(x::Int, y::Int)
    return x + y
end

@code_native add(2, 3)

    .text
; Function add {
; Location: REPL[1]:2
; Function +
; {  # REPL[1], line 2:
    addsd   %xmm1, %xmm0
;} # end of generated code
    retq
    nopw    %cs:(%rax,%rax)
;}