如何根据字典中其他键的值删除键值对？

def delete_pairs(dictionary, target_value):
    keys_to_delete = []
    for key, value in dictionary.items():
        if value == target_value:
            keys_to_delete.append(key)
    for key in keys_to_delete:
        del dictionary[key]

my_dict = {"A": 1, "B": 2, "C": 2, "D": 3}
delete_pairs(my_dict, 2)
print(my_dict)  # Output: {"A": 1, "D": 3}

import java.util.*;

public class DictionaryManipulation {
    public static void main(String[] args) {
        HashMap<String, Integer> dictionary = new HashMap<>();
        dictionary.put("A", 1);
        dictionary.put("B", 2);
        dictionary.put("C", 2);
        dictionary.put("D", 3);
        
        deletePairs(dictionary, 2);
        
        System.out.println(dictionary);  // Output: {A=1, D=3}
    }
    
    public static void deletePairs(HashMap<String, Integer> dictionary, int targetValue) {
        ArrayList<String> keysToDelete = new ArrayList<>();
        for (Map.Entry<String, Integer> entry : dictionary.entrySet()) {
            if (entry.getValue() == targetValue) {
                keysToDelete.add(entry.getKey());
            }
        }
        for (String key : keysToDelete) {
            dictionary.remove(key);
        }
    }
}

function deletePairs(dictionary, targetValue) {
    var keysToDelete = [];
    for (var key in dictionary) {
        if (dictionary.hasOwnProperty(key) && dictionary[key] === targetValue) {
            keysToDelete.push(key);
        }
    }
    for (var i = 0; i < keysToDelete.length; i++) {
        delete dictionary[keysToDelete[i]];
    }
}

var myDictionary = {"A": 1, "B": 2, "C": 2, "D": 3};
deletePairs(myDictionary, 2);
console.log(myDictionary);  // Output: {A: 1, D: 3}