如何根据模块路径在python包中创建文件？

import os

def create_file(module_path, file_name):
    # 获取当前脚本所在目录的绝对路径
    base_path = os.path.dirname(os.path.abspath(__file__))
    
    # 根据模块路径创建目录
    package_path = os.path.join(base_path, *module_path.split('.'))
    os.makedirs(package_path, exist_ok=True)
    
    # 创建文件
    file_path = os.path.join(package_path, file_name)
    with open(file_path, 'w') as file:
        file.write('This is a new file.')

# 示例调用
create_file('my_package.my_module', 'new_file.txt')