如何检查数字是浮点型还是整型？

def check_number_type(number):
    if isinstance(number, int):
        return "整型"
    elif isinstance(number, float):
        return "浮点型"
    else:
        return "未知类型"

# 示例
print(check_number_type(10))       # 输出: 整型
print(check_number_type(10.0))     # 输出: 浮点型
print(check_number_type(10.5))     # 输出: 浮点型

function checkNumberType(number) {
    if (Number.isInteger(number)) {
        return "整型";
    } else {
        return "浮点型";
    }
}

// 示例
console.log(checkNumberType(10));       // 输出: 整型
console.log(checkNumberType(10.0));     // 输出: 整型
console.log(checkNumberType(10.5));     // 输出: 浮点型

public class NumberTypeChecker {
    public static String checkNumberType(Number number) {
        if (number instanceof Integer) {
            return "整型";
        } else if (number instanceof Float || number instanceof Double) {
            return "浮点型";
        } else {
            return "未知类型";
        }
    }

    public static void main(String[] args) {
        System.out.println(checkNumberType(10));       // 输出: 整型
        System.out.println(checkNumberType(10.0f));    // 输出: 浮点型
        System.out.println(checkNumberType(10.5));     // 输出: 浮点型
    }
}

using System;

public class NumberTypeChecker
{
    public static string CheckNumberType(object number)
    {
        if (number is int || number is long || number is short || number is byte)
        {
            return "整型";
        }
        else if (number is float || number is double || number is decimal)
        {
            return "浮点型";
        }
        else
        {
            return "未知类型";
        }
    }

    public static void Main()
    {
        Console.WriteLine(CheckNumberType(10));       // 输出: 整型
        Console.WriteLine(CheckNumberType(10.0f));    // 输出: 浮点型
        Console.WriteLine(CheckNumberType(10.5));     // 输出: 浮点型
    }
}