如何生成连续数字列表？

# 生成从1到10的递增序列
sequence = list(range(1, 11))
print(sequence)  # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

# 生成从10到1的递减序列
sequence = list(range(10, 0, -1))
print(sequence)  # 输出: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

# 生成指定范围的序列
start = 5
end = 15
sequence = list(range(start, end + 1))
print(sequence)  # 输出: [5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

// 生成从1到10的递增序列
let sequence = Array.from({length: 10}, (_, i) => i + 1);
console.log(sequence);  // 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

// 生成从10到1的递减序列
sequence = Array.from({length: 10}, (_, i) => 10 - i);
console.log(sequence);  // 输出: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

// 生成指定范围的序列
let start = 5;
let end = 15;
sequence = Array.from({length: end - start + 1}, (_, i) => start + i);
console.log(sequence);  // 输出: [5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        // 生成从1到10的递增序列
        List<Integer> sequence = new ArrayList<>();
        for (int i = 1; i <= 10; i++) {
            sequence.add(i);
        }
        System.out.println(sequence);  // 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

        // 生成从10到1的递减序列
        sequence.clear();
        for (int i = 10; i >= 1; i--) {
            sequence.add(i);
        }
        System.out.println(sequence);  // 输出: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

        // 生成指定范围的序列
        int start = 5;
        int end = 15;
        sequence.clear();
        for (int i = start; i <= end; i++) {
            sequence.add(i);
        }
        System.out.println(sequence);  // 输出: [5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
    }
}