如何用Php将不同的Json数据保存到Mysql的同一数据库表中

<?php
// 连接到MySQL数据库
$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database";

$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
    die("连接失败: " . mysqli_connect_error());
}

// JSON数据
$jsonData1 = '{"name": "John", "age": 30, "city": "New York"}';
$jsonData2 = '{"name": "Jane", "age": 25, "city": "London"}';

// 解析JSON数据
$data1 = json_decode($jsonData1, true);
$data2 = json_decode($jsonData2, true);

// 插入数据到数据库表
$sql = "INSERT INTO your_table (name, age, city) VALUES ('".$data1['name']."', ".$data1['age'].", '".$data1['city']."')";
mysqli_query($conn, $sql);

$sql = "INSERT INTO your_table (name, age, city) VALUES ('".$data2['name']."', ".$data2['age'].", '".$data2['city']."')";
mysqli_query($conn, $sql);

mysqli_close($conn);
?>