如何等待20秒让用户按任意键？

import time

print("请按任意键继续，或等待20秒...")
start_time = time.time()
while True:
    if time.time() - start_time >= 20:
        break
    if input() != "":
        break

import java.util.Scanner;

public class WaitForUserInput {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("请按任意键继续，或等待20秒...");
        long startTime = System.currentTimeMillis();
        while (System.currentTimeMillis() - startTime < 20000) {
            if (scanner.hasNextLine()) {
                break;
            }
        }
    }
}

const readline = require("readline");

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

console.log("请按任意键继续，或等待20秒...");
const startTime = Date.now();
while (Date.now() - startTime < 20000) {
    rl.question("", () => {
        rl.close();
    });
}

using System;

class WaitForUserInput {
    static void Main() {
        Console.WriteLine("请按任意键继续，或等待20秒...");
        DateTime startTime = DateTime.Now;
        while (DateTime.Now.Subtract(startTime).TotalMilliseconds < 20000) {
            if (Console.KeyAvailable) {
                break;
            }
        }
    }
}