如何获取正则表达式匹配字符串的文件路径？

import os
import re

def get_file_paths(directory, pattern):
    file_paths = []
    pattern_regex = re.compile(pattern)
    
    for root, dirs, files in os.walk(directory):
        for file in files:
            file_path = os.path.join(root, file)
            if pattern_regex.match(file_path):
                file_paths.append(file_path)
    
    return file_paths

directory = '/path/to/directory'  # 指定文件夹路径
pattern = r'.*\.txt'  # 指定匹配的文件名格式，这里是以 .txt 结尾的文件

matched_file_paths = get_file_paths(directory, pattern)
for file_path in matched_file_paths:
    print(file_path)