如何获取每个组中最常见的n个项目

def get_most_common_projects(groups, n):
    result = {}
    
    for group in groups:
        project_counts = {}
        
        for project in group:
            if project in project_counts:
                project_counts[project] += 1
            else:
                project_counts[project] = 1
        
        sorted_projects = sorted(project_counts.items(), key=lambda x: x[1], reverse=True)
        result[group] = [project for project, count in sorted_projects[:n]]
    
    return result