如何获取MultipartFile的头部？

import org.springframework.web.bind.annotation.PostMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;
import org.springframework.web.multipart.MultipartFile;

@RestController
public class FileUploadController {

    @PostMapping("/upload")
    public String handleFileUpload(@RequestParam("file") MultipartFile file) {
        // 获取文件的原始名称
        String originalFilename = file.getOriginalFilename();
        // 获取文件的MIME类型
        String contentType = file.getContentType();
        // 获取文件的大小
        long size = file.getSize();

        // 获取文件的头部信息
        String header = null;
        try {
            header = file.getOriginalFilename(); // 这里假设头部信息包含在文件名中
            // 如果需要获取HTTP请求头，可以通过HttpServletRequest对象来获取
        } catch (Exception e) {
            e.printStackTrace();
        }

        // 处理文件上传的逻辑...

        return "File uploaded successfully: " + originalFilename;
    }
}

import javax.servlet.http.HttpServletRequest;

@PostMapping("/upload")
public String handleFileUpload(@RequestParam("file") MultipartFile file, HttpServletRequest request) {
    // 获取请求头信息
    String headerValue = request.getHeader("Header-Name");

    // 其他逻辑...

    return "File uploaded successfully";
}