如何获取URL的最后一个路径段

import re

def get_last_path_segment(url):
    # 解析URL
    pattern = r'^(?P<protocol>https?|ftp)://(?P<domain>[^/:]+)(?P<path>/.*)?$'
    match = re.match(pattern, url)
    if not match:
        return None

    # 获取路径部分
    path = match.group('path')
    if not path:
        return None

    # 分割路径部分
    segments = path.split('/')
    if not segments:
        return None

    # 获取最后一个路径段
    last_segment = segments[-1]
    return last_segment

# 示例用法
url = 'https://www.example.com/path/to/resource'
last_segment = get_last_path_segment(url)
print(last_segment)  # 输出：resource