如何解析datetime

import datetime

dt = datetime.datetime(2022, 1, 1, 12, 0, 0)

import datetime

# 获取当前日期和时间
now = datetime.datetime.now()
print(now)

# 获取日期和时间的各个部分
print(now.year)     # 年份
print(now.month)    # 月份
print(now.day)      # 日期
print(now.hour)     # 小时
print(now.minute)   # 分钟
print(now.second)   # 秒钟

# 比较日期和时间的大小
dt1 = datetime.datetime(2022, 1, 1)
dt2 = datetime.datetime(2022, 1, 2)
print(dt1 < dt2)    # True

# 进行日期和时间的加减运算
delta = datetime.timedelta(days=1)
dt3 = dt1 + delta
print(dt3)          # 2022-01-02 00:00:00

import datetime

# 将datetime对象格式化为字符串
dt = datetime.datetime(2022, 1, 1, 12, 0, 0)
str = dt.strftime("%Y-%m-%d %H:%M:%S")
print(str)  # 2022-01-01 12:00:00

# 将字符串解析为datetime对象
str = "2022-01-01 12:00:00"
dt = datetime.datetime.strptime(str, "%Y-%m-%d %H:%M:%S")
print(dt)   # 2022-01-01 12:00:00