如何计算两条线之间的交点，其中一条线由数据框列定义

import numpy as np

# 提取数据框中定义线的信息
line1_start = (df['x1'], df['y1'])
line1_end = (df['x2'], df['y2'])

# 计算线1的斜率和截距
line1_slope = (line1_end[1] - line1_start[1]) / (line1_end[0] - line1_start[0])
line1_intercept = line1_start[1] - line1_slope * line1_start[0]

# 假设线2的斜率和截距已知
line2_slope = 2
line2_intercept = 1

# 计算交点坐标
x_intersect = (line2_intercept - line1_intercept) / (line1_slope - line2_slope)
y_intersect = line1_slope * x_intersect + line1_intercept

# 检查交点是否在有效范围内
if (x_intersect >= min(line1_start[0], line1_end[0]) and x_intersect <= max(line1_start[0], line1_end[0]) and
    y_intersect >= min(line1_start[1], line1_end[1]) and y_intersect <= max(line1_start[1], line1_end[1])):
    print("交点坐标：({:.2f}, {:.2f})".format(x_intersect, y_intersect))
else:
    print("两条线段不相交")