以下代码将如何表现,特别是当双计数器达到其极限((2-2^-52)·2^1023)?
for (double i = 0; i < Double.POSITIVE_INFINITY; i++){
//do something
}
这段代码会像预期的那样运行(永远循环)还是在某个时候失败,为什么呢?
谢谢。
这是一个非常简单的理论:
theory Test
imports HOLCF
begin
fixrec down :: "'a u → 'a"
where "down (up x) = x"
end
它会给出以下错误:
Type unification failed: Clash of types "_ ⇒ _" and "_ → _"
Type error in application: operator not of function type
Operator: up :: ??'
我们尝试解决两个盒子之间的静态平衡问题: static_equilibrium_problem = StaticEquilibriumProblem(autodiff_plant, autodiff_plant.GetMyContextFromRoot(autodiff_context), set())
result = Solve(static_equilibrium_problem.prog()) 并得到了这个错误: RuntimeError: Signed distance queries between shapes 'Box' and 'Box'
我使用的是OpenCV 4.1.1。并有以下目标
给出float32的大小(m,n,2)的Mat,为每个通道创建单独的Mat头,这样就可以将其写入,而无需复制图像数据。
我想做的是:
const int mat_sz[]{shape_.height, shape_.width, 2};
Mat cost(3, mat_sz, CV_32F);
Mat channel1(
shape_, CV_32FC1, /* 1 channel Mat has FC1 type*/
cost.ptr<float>(), /* data ptr */
我正在查看在上给出的示例代码
此脚本中有以下代码:
# in this case the seeding of the centers is deterministic, hence we run the
# kmeans algorithm only once with n_init=1
pca = PCA(n_components=n_digits).fit(data)
bench_k_means(KMeans(init=pca.components_, n_clusters=n_digits, n_init=1),
name="PCA-based",