如何返回只包含奇数的新数组

function filterOddNumbers(arr) {
  return arr.filter(num => num % 2 !== 0);
}

// 使用示例
const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9];
const oddNumbers = filterOddNumbers(numbers);
console.log(oddNumbers); // 输出: [1, 3, 5, 7, 9]

def filter_odd_numbers(arr):
    return [num for num in arr if num % 2 != 0]

# 使用示例
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9]
odd_numbers = filter_odd_numbers(numbers)
print(odd_numbers)  # 输出: [1, 3, 5, 7, 9]

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class OddNumbersFilter {
    public static List<Integer> filterOddNumbers(int[] arr) {
        List<Integer> oddNumbers = new ArrayList<>();
        for (int num : arr) {
            if (num % 2 != 0) {
                oddNumbers.add(num);
            }
        }
        return oddNumbers;
    }

    public static void main(String[] args) {
        int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9};
        List<Integer> oddNumbers = filterOddNumbers(numbers);
        System.out.println(oddNumbers); // 输出: [1, 3, 5, 7, 9]
    }
}