如果一个字符串不在一组字符串中，那么最快的查找方法是什么？

# 创建哈希表
hash_set = set(["apple", "banana", "cherry"])

# 查找字符串
def string_not_in_hash_set(target):
    return target not in hash_set

print(string_not_in_hash_set("date"))  # 输出: True

from collections import defaultdict

class TrieNode:
    def __init__(self):
        self.children = defaultdict(TrieNode)
        self.is_end_of_word = False

class Trie:
    def __init__(self):
        self.root = TrieNode()

    def insert(self, word):
        node = self.root
        for char in word:
            node = node.children[char]
        node.is_end_of_word = True

    def search(self, word):
        node = self.root
        for char in word:
            if char not in node.children:
                return False
            node = node.children[char]
        return node.is_end_of_word

# 创建Trie树
trie = Trie()
trie.insert("apple")
trie.insert("banana")
trie.insert("cherry")

# 查找字符串
def string_not_in_trie(target):
    return not trie.search(target)

print(string_not_in_trie("date"))  # 输出: True

import mmh3
from bitarray import bitarray

class BloomFilter:
    def __init__(self, size, hash_count):
        self.size = size
        self.hash_count = hash_count
        self.bit_array = bitarray(size)
        self.bit_array.setall(0)

    def add(self, item):
        for seed in range(self.hash_count):
            result = mmh3.hash(item, seed) % self.size
            self.bit_array[result] = 1

    def lookup(self, item):
        for seed in range(self.hash_count):
            result = mmh3.hash(item, seed) % self.size
            if self.bit_array[result] == 0:
                return False
        return True

# 创建布隆过滤器
bloom_filter = BloomFilter(500000, 7)

# 添加字符串到布隆过滤器
strings = ["apple", "banana", "cherry"]
for string in strings:
    bloom_filter.add(string)

# 查找字符串
def string_not_in_bloom_filter(target):
    return not bloom_filter.lookup(target)

print(string_not_in_bloom_filter("date"))  # 输出: 可能为True，但存在假阳性