如果一个数组中的数字存在于另一个数组中，如何删除该数组中的数字

function removeCommonElements(arr1, arr2) {
  return arr1.filter(item => !arr2.includes(item));
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];

const result = removeCommonElements(array1, array2);
console.log(result); // 输出: [1, 2]

def remove_common_elements(arr1, arr2):
    return [item for item in arr1 if item not in arr2]

array1 = [1, 2, 3, 4, 5]
array2 = [3, 4, 5, 6, 7]

result = remove_common_elements(array1, array2)
print(result)  # 输出: [1, 2]

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        Integer[] array1 = {1, 2, 3, 4, 5};
        Integer[] array2 = {3, 4, 5, 6, 7};

        List<Integer> list1 = new ArrayList<>(Arrays.asList(array1));
        List<Integer> list2 = Arrays.asList(array2);

        list1.removeAll(list2);
        System.out.println(list1); // 输出: [1, 2]
    }
}

def remove_common_elements_efficient(arr1, arr2):
    set2 = set(arr2)
    return [item for item in arr1 if item not in set2]

# 使用示例与之前相同