'B'
d['c'] = 'C'
for key, value in d.items():
print key, value
OrderedDict:
a A
b B
c C
相等比较
比较两个词典是否相等...,普通词典比较只看内容,内容相同即判定相等为真;而OrderedDict同时会考虑顺序,item被添加的顺序。...k in s:
d[k] += 1
d.items()
[('i', 4), ('p', 2), ('s', 4), ('m', 1)]
set
和list功能类似,但返回set(),剔除了重复元素...print collections.Counter(['a', 'b', 'c', 'a', 'b', 'b'])
print collections.Counter({'a':2, 'b':3, 'c...c = collections.Counter('abcdaab')
c.most_common(2)
[('a', 3), ('b', 2)]