将数据从Promise返回到GraphQL

const { graphql, buildSchema } = require('graphql');

// 定义GraphQL模式
const schema = buildSchema(`
  type User {
    id: ID!
    name: String!
    email: String!
  }

  type Query {
    getUser(id: ID!): User
  }
`);

// 模拟从数据库中获取用户数据的异步操作
const getUserFromDatabase = (id) => {
  return new Promise((resolve, reject) => {
    // 模拟异步操作
    setTimeout(() => {
      // 假设从数据库中获取用户数据
      const user = {
        id: id,
        name: 'John Doe',
        email: 'john@example.com'
      };
      resolve(user);
    }, 1000);
  });
};

// 定义解析器函数
const root = {
  getUser: ({ id }) => {
    // 调用异步操作并返回Promise对象
    return getUserFromDatabase(id);
  }
};

// 执行GraphQL查询
const query = `
  query {
    getUser(id: "1") {
      id
      name
      email
    }
  }
`;

graphql(schema, query, root)
  .then(result => {
    console.log(result);
  })
  .catch(error => {
    console.error(error);
  });