将Java枚举序列化为XML的最佳做法是什么？

   <groupId>javax.xml.bind</groupId>
   <artifactId>jaxb-api</artifactId>
   <version>2.3.1</version>
</dependency>

public enum Color {
    RED,
    GREEN,
    BLUE
}

import javax.xml.bind.annotation.XmlEnum;
import javax.xml.bind.annotation.XmlType;

@XmlEnum
@XmlType(name = "color")
public enum Color {
    RED,
    GREEN,
    BLUE
}

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import java.io.StringReader;
import java.io.StringWriter;

public class Main {
    public static void main(String[] args) throws JAXBException {
        // 创建JAXB上下文
        JAXBContext jaxbContext = JAXBContext.newInstance(Color.class);

        // 创建一个枚举对象
        Color color = Color.RED;

        // 将枚举对象序列化为XML
        StringWriter sw = new StringWriter();
        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(color, sw);
        String xmlString = sw.toString();

        // 将XML反序列化为枚举对象
        StringReader sr = new StringReader(xmlString);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        Color unmarshalledColor = (Color) unmarshaller.unmarshal(sr);

        // 输出结果
        System.out.println("Serialized XML: " + xmlString);
        System.out.println("Unmarshalled color: " + unmarshalledColor);
    }
}

Serialized XML: <?xml version="1.0" encoding="UTF-8" standalone="yes"?<color>RED</color>
Unmarshalled color: RED