当我尝试将UnsafeMutableRawPointer作为函数参数传递时,我得到以下错误: A C function pointer can only be formed from a reference, _ third: Int32, _ ptrs: ((UnsafeMutableRawPointer?) -> Void)!)我如何通过我的函数传递指针?
首先,我通过桥接头将C头导入header中。然后,我尝试使用指向快速对象的指针来调用foo_func。
var x:foo_t?(aka 'Optional<OpaquePointer>') to expected argument type 'UnsafeMutableRawPointer?'cannot convert value of type 'UnsafeMutablePointer<_>' to expected argument type 'Unsaf
我有一个用于myCGEventCallback的CGEventTap函数,它的参数是"refcon:UnsafeMutableRawPointer?“。我将主ViewController作为回调的指针传递给
let pointer = UnsafeMutableRawPointer(Unmanaged.passRetained(self).toOpaqueSender.someFunction()它在函数运行之前就崩溃了,所以我假设它在访问发
protocol class A {}extension B: P {} 此外,我还有一个回调闭包,它的主要参数是传递给某个C应用编程接口函数的UnsafeMutableRawPointer: SomeCFunction(…, …, { (pointerToEitherAOrB: UnsafeMutableRawPointer
:
Cannot invoke initializer for type 'UnsafeMutablePointer<UInt32>' with an argument list of type '(UnsafeMutableRawPointer是否有一种方法可以在初始化时将UnsafeMutableRawPointer转换为UnsafeMutablePointer作为参数接受的任何适当类型?
有一个带有变异方法的struct,我可以将struct的一个实例作为inout参数传递并调用该方法。传递的实例将被修改,如下面的示例所示。我的问题是,如何调用切入点上的变异函数,从而修改原始实例。fun f(p: UnsafeMutableRawPointer){
var s = p.assumingMemoryBound(to: S.self).pointee // could also