将char数组转换为时间结构

#include <stdio.h>
#include <time.h>

int main() {
    char time_str[] = "2022-01-01 10:30:00";
    struct tm tm_time;
    strptime(time_str, "%Y-%m-%d %H:%M:%S", &tm_time);
    time_t timestamp = mktime(&tm_time);
    printf("Timestamp: %ld\n", timestamp);
    return 0;
}

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class Main {
    public static void main(String[] args) {
        String timeStr = "2022-01-01 10:30:00";
        SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        try {
            Date date = dateFormat.parse(timeStr);
            long timestamp = date.getTime();
            System.out.println("Timestamp: " + timestamp);
        } catch (ParseException e) {
            e.printStackTrace();
        }
    }
}

from datetime import datetime

time_str = "2022-01-01 10:30:00"
datetime_obj = datetime.strptime(time_str, "%Y-%m-%d %H:%M:%S")
timestamp = datetime_obj.timestamp()
print("Timestamp: ", timestamp)