将scala嵌套列表转换为java.util.List

import java.util.{ArrayList, List}

def convertToList(input: List[Any]): java.util.List[Any] = {
  val result = new ArrayList[Any]()
  for (item <- input) {
    item match {
      case list: List[_] =>
        result.add(convertToList(list))
      case _ =>
        result.add(item)
    }
  }
  result
}

val scalaList = List(1, List(2, 3), List(4, List(5, 6)))
val javaList = convertToList(scalaList)