当我单独运行这行代码时,我得到的预期结果是1: sum(case when facilityname like '%AT%' then count(status) else 0 end) as AT_all_status但是,当我同时运行多个case语句时,如本例所示,所有case语句都返回NULL: sum(case when facilityname like '%AT%' then count(status)')
我有一个查询,它使用用户定义函数中的嵌套CTE。我必须使用嵌套的CTE,因为我想重用前面selects中的一些计算/case语句。查询看起来类似于下面的内容。;with cte1 as select a, b from Table1(
case when a =1 then 1 else 0 end as c, bfrom cte
如何编写一个SQL查询,通过执行以下两个查询(步骤)来获得相同的结果:SELECT old_id, new_id FROM history WHERE flag = 1;+----------+--------+| 33 | 44 |+--------+--------+UPDATE other_tabla SET somefk_id = <em
我试图通过以下逻辑得到两个数字的和:X=y+j,基于这个逻辑,我用SUM()函数编写了presto查询,以求x和y的和,但我得到了Presto语法错误。SELECT WHEN source = 'x' THEN num_tasks END) + sum(CASE WHENsource = 'y' THEN num
试图在zend framework 1中编写以下查询: SUM(CASE WHEN column2 = 'value1' THEN column3 END) AS 'mySpecialSum',WHERE column4='value2' AND column5='value3'$select = $this->select()
->from('m