平衡括号检测？

def is_balanced(s):
    stack = []
    mapping = {')': '(', ']': '[', '}': '{', '>': '<'}
    
    for char in s:
        if char in mapping:
            top_element = stack.pop() if stack else '#'
            if mapping[char] != top_element:
                return False
        else:
            stack.append(char)
    
    return not stack

# 测试示例
print(is_balanced("()"))  # True
print(is_balanced("([])"))  # True
print(is_balanced("([)]"))  # False
print(is_balanced("{[()]}"))  # True
print(is_balanced("((())"))  # False