循环遍历包含列表的表达式的方案

my_list = [1, 2, 3, 4, 5]
for item in my_list:
    print(item)

let myList = [1, 2, 3, 4, 5];
for (let i = 0; i < myList.length; i++) {
    console.log(myList[i]);
}

my_list = [1, 2, 3, 4, 5]
iterator = iter(my_list)
while True:
    try:
        item = next(iterator)
        print(item)
    except StopIteration:
        break

my_list = [1, 2, 3, 4, 5]
result = list(map(lambda x: x * 2, my_list))
print(result)  # 输出: [2, 4, 6, 8, 10]

let myList = [1, 2, 3, 4, 5];
let result = myList.map(x => x * 2);
console.log(result);  // 输出: [2, 4, 6, 8, 10]

if my_list:
    for item in my_list:
        print(item)
else:
    print("列表为空")

for i in range(len(my_list)):
    print(my_list[i])

def my_generator(lst):
    for item in lst:
        yield item * 2

for result in my_generator(my_list):
    print(result)