我可以用下面的代码来得到WiFi的名字,我希望通过编程选择Wifi,我该怎么办?
看来wifiInfo.ssid是val,不能分配它!
我将所需的权限设置为
<!-- in AndroidManifest.xml -->
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" />
然后在代码中
<!-- in Activity class -->
var wifiManager = mContext.applicationContext.getSystemSe
我有这个代码,应该用给定的ESSID和密码连接到wifi。以下是代码:
def wifi_connect(essid, password):
# Connect to the wifi. Based on the example in the micropython
# documentation.
wlan = network.WLAN(network.STA_IF)
wlan.active(True)
if not wlan.isconnected():
print('connecting to network ' + essid + '...')