按每行奇数计数过滤矩阵

def filter_odd_rows(matrix):
    filtered_matrix = []
    for i in range(len(matrix)):
        if i % 2 != 0:  # 判断是否为奇数行
            filtered_matrix.append(matrix[i])
    return filtered_matrix

def count_elements(matrix):
    count = []
    for row in matrix:
        count.append(len(row))
    return count

# 示例矩阵
matrix = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9],
    [10, 11, 12]
]

filtered_matrix = filter_odd_rows(matrix)
element_count = count_elements(filtered_matrix)

print("过滤后的矩阵：")
for row in filtered_matrix:
    print(row)

print("每行奇数行的元素个数：")
for count in element_count:
    print(count)

过滤后的矩阵：
[4, 5, 6]
[10, 11, 12]
每行奇数行的元素个数：
3
3