按项目名称长度对列表进行排序的最佳方法

def compare_by_name_length(item1, item2):
    name1 = item1['name']
    name2 = item2['name']
    length1 = len(name1)
    length2 = len(name2)
    
    if length1 < length2:
        return -1
    elif length1 > length2:
        return 1
    else:
        return 0

# 示例项目列表
projects = [
    {'name': 'Project A'},
    {'name': 'Project B'},
    {'name': 'Project C'},
    {'name': 'Project D'},
    {'name': 'Project E'}
]

# 使用自定义的比较函数对项目列表进行排序
sorted_projects = sorted(projects, key=compare_by_name_length)

# 打印排序结果
for project in sorted_projects:
    print(project['name'])