有没有一种方法可以复制派生类指针的向量而不将其强制转换为基类？

#include <iostream>
#include <vector>

template<typename T>
class PointerVector {
public:
    void add(T* ptr) {
        pointers.push_back(ptr);
    }

    T* get(int index) {
        return pointers[index];
    }

private:
    std::vector<T*> pointers;
};

// 示例用法
class Base {
public:
    virtual void print() {
        std::cout << "Base" << std::endl;
    }
};

class Derived : public Base {
public:
    void print() override {
        std::cout << "Derived" << std::endl;
    }
};

int main() {
    PointerVector<Base> vector;
    Derived derived;

    vector.add(&derived);

    Base* ptr = vector.get(0);
    ptr->print();  // 输出 "Derived"

    return 0;
}