有没有办法在脚本中暂停或等待片刻？

import time

time.sleep(1)  # 等待1秒

function sleep(ms) {
  return new Promise(resolve => setTimeout(resolve, ms));
}

async function example() {
  console.log('Starting...');
  await sleep(1000); // 等待1秒
  console.log('...1 second later');
}

example();

import java.util.concurrent.TimeUnit;

public class SleepExample {
  public static void main(String[] args) throws InterruptedException {
    System.out.println("Starting...");
    TimeUnit.SECONDS.sleep(1); // 等待1秒
    System.out.println("...1 second later");
  }
}

using System;
using System.Threading.Tasks;

class SleepExample {
  static async Task Main() {
    Console.WriteLine("Starting...");
    await Task.Delay(1000); // 等待1秒
    Console.WriteLine("...1 second later");
  }
}

<?php

echo "Starting...\n";
sleep(1); // 等待1秒
echo "...1 second later\n";

?>