有没有办法在Python的目录中找到特定的子文件夹？

import os

# 遍历目录下的所有子文件夹
def find_subdirectories(directory):
    subdirectories = []
    for root, dirs, files in os.walk(directory):
        for d in dirs:
            subdirectories.append(os.path.join(root, d))
    return subdirectories

# 在目录中查找特定的子文件夹
def find_specific_subdirectory(directory, name):
    for root, dirs, files in os.walk(directory):
        for d in dirs:
            if d == name:
                return os.path.join(root, d)
    return None

# 示例用法
directory = '/path/to/parent/directory'
subdirectories = find_subdirectories(directory)
specific_subdirectory = find_specific_subdirectory(directory, 'specific_name')

import glob

# 查找目录下的所有子文件夹
def find_subdirectories(directory):
    return [folder for folder in glob.glob(f'{directory}/*') if os.path.isdir(folder)]

# 查找特定的子文件夹
def find_specific_subdirectory(directory, name):
    subdirectories = find_subdirectories(directory)
    for folder in subdirectories:
        if os.path.basename(folder) == name:
            return folder
    return None

# 示例用法
directory = '/path/to/parent/directory'
subdirectories = find_subdirectories(directory)
specific_subdirectory = find_specific_subdirectory(directory, 'specific_name')