有没有办法在windows10服务的隐藏gui上按一个按钮？

 public class Win32Api

 {

     [DllImport("user32.dll")]

     public static extern IntPtr FindWindow(string lpClassName, string lpWindowName);

     [DllImport("user32.dll")]

     public static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChildAfter, string lpszClass, string lpszWindow);

     [DllImport("user32.dll")]

     public static extern IntPtr SendMessage(IntPtr hWnd, uint Msg, IntPtr wParam, IntPtr lParam);

 }

 public class Program

 {

     public static void Main()

     {

         IntPtr window = Win32Api.FindWindow(null, "服务"); // 替换为服务窗口的标题

         IntPtr button = Win32Api.FindWindowEx(window, IntPtr.Zero, "Button", "按钮"); // 替换为按钮的标题

         Win32Api.SendMessage(button, 0x0201, IntPtr.Zero, IntPtr.Zero); // 模拟鼠标左键按下

         Win32Api.SendMessage(button, 0x0202, IntPtr.Zero, IntPtr.Zero); // 模拟鼠标左键释放

     }

 }

 "@

 [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms") | Out-Null

 [System.Windows.Forms.MessageBox]::Show("按下按钮成功！", "提示")

 ```