查找给定数组中重复和缺失的数字

def findDuplicatesAndMissing(nums):
    n = len(nums)
    count = {}
    duplicate = -1
    missing = -1
    
    # 计算每个数字出现的次数
    for num in nums:
        if num in count:
            count[num] += 1
        else:
            count[num] = 1
    
    # 找到重复的数字和缺失的数字
    for i in range(1, n+1):
        if i in count:
            if count[i] == 2:
                duplicate = i
        else:
            missing = i
    
    return duplicate, missing

# 测试示例
nums = [1, 2, 2, 4]
duplicate, missing = findDuplicatesAndMissing(nums)
print("重复的数字:", duplicate)
print("缺失的数字:", missing)