根据同一字典中不同嵌套列表中的值，删除嵌套在字典中的列表条目

def remove_nested_items(dictionary):
    keys_to_remove = []  # 存储需要删除的键

    for key, value in dictionary.items():
        if isinstance(value, list):  # 检查值是否为列表
            for item in value:
                if any(item in other_list for other_list in dictionary.values() if isinstance(other_list, list) and other_list is not value):
                    value.remove(item)  # 从当前列表中删除元素

            if not value:  # 如果列表为空
                keys_to_remove.append(key)  # 添加需要删除的键

    for key in keys_to_remove:
        del dictionary[key]  # 从字典中删除键值对

    return dictionary