根据条件合并列表中的项目

function mergeLists(list1, list2, condition) {
  let mergedList = [];
  
  for (let item of list1) {
    if (condition(item)) {
      mergedList.push(item);
    }
  }
  
  for (let item of list2) {
    if (condition(item)) {
      mergedList.push(item);
    }
  }
  
  return mergedList;
}

// 示例用法
let list1 = [1, 2, 3, 4, 5];
let list2 = [6, 7, 8, 9, 10];

function isEven(num) {
  return num % 2 === 0;
}

let mergedList = mergeLists(list1, list2, isEven);
console.log(mergedList); // 输出 [2, 4, 6, 8, 10]