用urllib2而不是requests抓取谷歌学者

import urllib.request
from urllib.error import HTTPError, URLError

url = 'https://scholar.google.com/scholar?q=python'

try:
    response = urllib.request.urlopen(url)
    html = response.read()
    print(html)
except HTTPError as e:
    print(f'HTTP 错误: {e.code}')
except URLError as e:
    print(f'URL 错误: {e.reason}')

try:
    response = urllib.request.urlopen(url)
except HTTPError as e:
    print(f'HTTP 错误: {e.code}')

try:
    response = urllib.request.urlopen(url)
except URLError as e:
    print(f'URL 错误: {e.reason}')

import urllib.request

url = 'https://scholar.google.com/scholar?q=python'
headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3'}

req = urllib.request.Request(url, headers=headers)
try:
    response = urllib.request.urlopen(req)
    html = response.read()
    print(html)
except HTTPError as e:
    print(f'HTTP 错误: {e.code}')
except URLError as e:
    print(f'URL 错误: {e.reason}')