筛选pandas列，这是两个日期之间的差异

import pandas as pd

# 创建一个示例DataFrame
data = {'日期': ['2022-01-01', '2022-01-02', '2022-01-03', '2022-01-04'],
        '数值': [10, 20, 30, 40]}
df = pd.DataFrame(data)

# 将日期列转换为datetime类型
df['日期'] = pd.to_datetime(df['日期'])

# 计算两个日期之间的差异
diff = df['日期'].diff()

# 将差异添加为新的一列
df['日期差异'] = diff

print(df)

          日期  数值     日期差异
0 2022-01-01  10      NaT
1 2022-01-02  20 1 days
2 2022-01-03  30 1 days
3 2022-01-04  40 1 days

filtered_df = df[df['日期差异'] == pd.Timedelta(days=1)]
print(filtered_df)

          日期  数值     日期差异
1 2022-01-02  20 1 days
2 2022-01-03  30 1 days
3 2022-01-04  40 1 days