继承--如何在C++的继承类中只调用一个构造函数？

#include <iostream>

class Base {
public:
    Base(int value) {
        std::cout << "Base constructor called with value: " << value << std::endl;
    }
};

class Derived : public Base {
public:
    Derived(int value) : Base(value) {
        // 子类构造函数中使用初始化列表调用父类构造函数
        std::cout << "Derived constructor called with value: " << value << std::endl;
    }
};

int main() {
    Derived derived(10);
    return 0;
}

Base constructor called with value: 10
Derived constructor called with value: 10