在我的应用程序中,我想通过在线流媒体显示视频,但视频无法启动,并且我收到错误消息“对不起,无法播放此视频”,并且logcat错误为
couldn't open file on client side trying server side and mediaplayer error (1,-1004)
这是什么意思。
我需要把视频解码成帧。我可以在mime类型的视频中这样做,但是它不适用于
for (int i = 0; i < extractor.getTrackCount(); i++) {
MediaFormat format = extractor.getTrackFormat(i);
String mime = format.getString(MediaFormat.KEY_MIME);
System.out.println(mime);
if (mime.sta
我正试图皈依:
Public Event GoogleAPIRequestCompleted(Status As HttpStatusCode, Response As String)
Private Sub OnGoogleAPIRequestCompleted(Status As HttpStatusCode, Response As String)
If p_SynchronizationContext IsNot Nothing Then
p_SynchronizationContext.Send(New Threading.SendOrPostCallba
嗨,我想在我的应用程序上播放远程视频。网址为:
我使用的AVKit与此代码,但屏幕和音频不工作。我只看到前进的进度条。
let player = AVPlayer(url: url)
// Create a new AVPlayerViewController and pass it a reference to the player.
let controller = AVPlayerViewController()
controller.player = player
controller.player?.
我正在用laravel制作一个像udemy这样的视频学习平台,但我遇到了一些问题。我使用的是拉拉铰刀包,我创建了一个控制器:
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use Raju\Streamer\Helpers\VideoStream;
class StreamController extends Controller
{
public function stream($filename)
{
$videosDir = config('lara