重复迭代numpy数组的相同子集的最快方法

import numpy as np

# 创建一个示例数组
arr = np.array([1, 2, 3, 4, 5])

# 定义子集
subset = arr[1:3]

# 重复子集
repeated_subsets = np.tile(subset, (3, 1)).T.flatten()[:len(arr)*3]
print(repeated_subsets)

import numpy as np

# 创建一个示例数组
arr = np.array([1, 2, 3, 4, 5])

# 定义子集
subset = arr[1:3]

# 使用np.tile重复子集
repeated_subsets = np.tile(subset, 3)
print(repeated_subsets)

import numpy as np

# 创建一个示例数组
arr = np.array([1, 2, 3, 4, 5])

# 定义子集
subset = arr[1:3]

# 使用循环重复子集
repeated_subsets = np.concatenate([subset for _ in range(3)])
print(repeated_subsets)

import numpy as np

# 创建一个示例数组
arr = np.array([1, 2, 3, 4, 5])

# 定义子集
subset = arr[1:3]

# 使用生成器表达式逐个产生重复元素
repeated_subsets_gen = (item for _ in range(3) for item in subset)
print(list(repeated_subsets_gen))