我正在将代码库从Python2升级到Python3。
Python3代码中的测试用例失败,因为set()函数生成的顺序与Python2不同。
例如:
# Here in Python 2.7 the PYTHONHASHSEED is disabled.
list = {"it","is","rishabh","Mishra"}
# Below, in Python 3
list = {"rishabh","it","is","mishra"}
我希望顺序与Pyth
我有一个python脚本,它在运行时会产生以下错误:
import urllib2
File "C:\Python27\lib\urllib2.py", line 94, in <module>
import httplib
File "C:\Python27\lib\httplib.py", line 73, in <module>
from urlparse import urlsplit
File "C:\Python27\lib\urlparse.py", line 119, in <module>
f
这就是我要犯的错误
Traceback (most recent call last):
File "detectron/utils/subprocess.py", line 28, in <module> import numpy as np
File "/usr/local/lib/python2.7/dist-packages/numpy/__init__.py", line 142, in <module> from . import add_newdocs
File "/usr/local/lib/pytho
用这个剧本
---
- name: ReadJsonfile
hosts: localhost
tasks:
- name: Display the JSON file content
shell: "cat config.json"
register: result
- name: save the Json data to a Variable as a Fact
set_fact:
jsondata: "{{ result.stdout | from_json }}"
我正在使用python 3.4.3 (.py)脚本中的以下程序
number = {1,2,1,4,5,6,9}
print(number)
number.add(-5) # adding some random number to the set
number.remove(3) # in this line python reports KeyError
print(number)
number.pop()
print(number)
但是当我使用其他索引时
number.remove(2) # works fine
number.remove(5) # works fine
有没
如何使mac上的zsh使用我的/usr/local/bin/python中的python 2.7.6而不是/usr/bin/python中的python2.7.5?(无需在我想运行的脚本之前键入/usr/local/bin/python )。我在.zprofile上的路径设置是:
# Setting PATH for Python 2.7
# The orginal version is saved in .zprofile.pysave
PATH="/Library/Frameworks/Python.framework/Versions/2.7/bin:${PATH}"
e
考虑这两种代码,我在python控制台中运行:
l=[]
for i in range(0,1000): l.append("."*1000000)
# if you check your taskmanager now, python is using nearly 900MB
del l
# now python3 immediately free-d the memory
现在考虑这一点:
l=[]
for i in range(0,1000): l.append("."*1000000)
l.append(l)
# if you check your t
import random
userKeywords = {"hi","hello","wassup","what'sup","greetings","sup","henlo","que onda","hola","hey","waddup"}
machineResponses = {"hello", "Hello there, I am a bot", "greetin
为什么只有在通过函数调用时才更改元素的顺序?是什么决定了这个命令?
# test_set_order.py
def unpack(input):
print('input is {}'.format(input))
result = []
for i in input:
result.extend(i)
return result
print(unpack({'A', 'B'}))
执行上述脚本将产生不同的输出:
$ python test_set_order.py
input is {'
我让这个regex ("^[-A-Z0-9-[O]]{1,8}$")从客户需求开始(通常不应该更改)。但是它在python中不起作用(它在C中工作)。
from re import search
var = "MY01C0DE"
regex = "^[-A-Z0-9-[O]]{1,8}$"
print(search(regex, var))
这个印不出来。
但是,如果我将正则表达式更改为"^[-A-NP-Z0-9]{1,8}$",这是可行的。
from re import search
var = "MY01C0DE
from django.db import models
from django.core.urlresolvers import reverse
class Gallery(models.Model):
Title = models.CharField(max_length=250)
Category = models.CharField(max_length=250)
Gallery_logo = models.CharField(max_length=1000)
def get_absolute_url(self):
return r
我正试图在CentOS6下构建python33.python-virtualenv。目前,我正在尝试将当前版本重新构建为:
我收到一个错误:/usr/lib/rpm/brp-scl-python-bytecompile: line 47: /usr/bin/python3.3: No such file or directory
知道我做错了什么吗?
注意:我是在模拟环境中这样做的,scl被定义为python33。
在Django中,我安装了新的软件包easy_thumbnails,adminsortable,和filer,但是当我想向网站添加新图像时,我得到了这个错误页面
TypeError at /en/admin/filer/folder/
unsupported operand type(s) for +: 'set' and 'tuple'
Request Method: GET
Request URL: http://127.0.0.1:8000/en/admin/filer/folder/?_popup=1
Django Version:
根据我对Python 2.7.2文档的解释Built-In Types 5.7 Set Types,应该可以通过将A传递给集合B来从集合B中删除集合A的元素set.remove(elem)或者set.discard(elem) 来自2.7.2的文档: 注意,将elem参数添加到__contains__() remove(),以及discard()方法可以是一个集合。 我将其解释为我可以传递一个set至remove(elem)或者discard(elem) 所有这些元素都将从目标集合中删除。我会用它来做一些奇怪的事情,比如移除字符串中的所有元音,或者remove all common wor
`python manage.py collectstatic Traceback (most recent call last): File "manage.py", line 21, in <module>
main() File "manage.py", line 17, in main
execute_from_command_line(sys.argv) File "/home/jet/venvfordjango/lib/python3.7/site-packages/django/core/manage