我了解到,late初始化器,即直接具有初始化赋值的声明,是延迟执行的: late final word = calculateWord(); // Will be initialized我假设变量是在构造函数中延迟初始化的,因为实例字段随后与那些直接与赋值一起具有初始化器的字段被分配。class Baz {
just a helper rather than a foolproof solution - ie. anyone may still save a pointer to obj etc. and accessit later class Access { Access(std::mutex& m, T& obj) : sl_(m), obj_(obj) {T& obj_; std::scoped_lock<std::mutex&