不过在开发过程中其实也遇到 time 在 AddDate 的一个坑,因此撰此薄文分享一下。 问题发现 AddDate 有三个参数,分别是年、月、日。...在官方文档中,对 time.AddDate 方法的说明如下: AddDate returns the time corresponding to adding the given number of years...简单翻译一下: AddDate 根据指定的年、月、日数字,加到原来的 time 类型值上并返回。...比如对于 2011-1-1 这个日期,执行 AddDate(-1, 2, 3) 会返回 2010-3-4 AddDate 将它的结果按实际日期进行标准化,所以,比如在10月31日加上一个月,会返回12月...上文解释的第二段就是坑所在:AddDate 函数中,year 参数等于 365 天,month 参数等于 30 天。
sql 多条件查询的一种简单的方法 以后我们做多条件查询,一种是排列结合,另一种是动态拼接SQL 如:我们要有两个条件,一个日期@addDate,一个是@name 第一种写法是 if (@addDate... is not null) and (@name '') select * from table where addDate = @addDate and name = @name else if... (@addDate is not null) and (@name ='') select * from table where addDate = @addDate else if(@addDate... is null) and (@name '') select * from table where and name = @name else if(@addDate is null) and... = @addDate or @addDate is null) and (name = @name or @name = '') 结果一调试,成功, 一点想法,有更好方法的,请指教!
static final long serialVersionUID = 1L; private String userId; private String userName; private Date addDate...setUserName(String userName) { this.userName = userName; } public Date getAddDate() { return addDate...; } public void setAddDate(Date addDate) { this.addDate = addDate; } } import java.util.Date...; } public void setAddDate(Date addDate) { this.addDate = addDate; } @Override public String...toString() { return "ChildrenUser [userId=" + userId + ", addDate=" + addDate + "]"; } } 测试程序如下
; } public void setAddDate(Date addDate) { this.addDate = addDate; } public...; } public void setAddDate(Date addDate) { this.addDate = addDate; } public...; } public void setAddDate(Date addDate) { this.addDate = addDate; } public..." jdbcType="TIMESTAMP" property="addDate" /> <result column="updatedate" jdbcType="TIMESTAMP"
"fruit": "小米12", "pic": "/src/assets/images/1.jpg", "price": 2999, "adddate..."fruit": "青柠", "pic": "/src/assets/images/1.jpg", "price": 5, "adddate..."fruit": "柚子", "pic": "/src/assets/images/2.jpg", "price": 4.5, "adddate..."fruit": "橘子", "pic": "/src/assets/images/3.jpg", "price": 3, "adddate..."fruit": "柠檬", "pic": "/src/assets/images/6.jpg", "price": 4, "adddate
INSERT INTO `user` VALUES ('5', '小蓝', '2001-01-01', '女', '上海嘉定', '2018-03-15'); 复制 2、查询时间范围 SELECT adddate...n100.i * 100 AS id FROM num n1 CROSS JOIN num AS n10 CROSS JOIN num AS n100 ) AS numlist WHERE adddate...n100.i * 100 AS id FROM num n1 CROSS JOIN num AS n10 CROSS JOIN num AS n100 ) AS numlist WHERE adddate...查看结果集 按月统计差不多,上面的懂了,下面的是一样的 SELECT left(temp.date,7), coalesce(u.unmber,0) 'number' from( SELECT adddate...+ n10.i * 10 AS id FROM num n1 CROSS JOIN num AS n10) a where a.id<=11 ) AS numlist WHERE adddate
now.Date() thisWeek := time.Date(year, month, day, 0, 0, 0, 0, time.Local) startTime = thisWeek.AddDate...(0, 0, offset+7*week).Format("2006-01-02") + " 00:00:00" endTime = thisWeek.AddDate(0, 0, offset+6...time.Now().Date() thisMonth := time.Date(year, month, 1, 0, 0, 0, 0, time.Local) startTime = thisMonth.AddDate...(0, mon, 0).Format("2006-01-02") + " 00:00:00" endTime = thisMonth.AddDate(0, mon+1, -1).Format("2006
"newsname"))%>[] 后台代码: //绑定新闻 private voidBindNews() { stringstrSQL ="Select top 11 newsid,newsname,adddate...From news Order By adddate Desc"; DataTabledt =SqlData.dataTable(strSQL); repNews.DataSource = dt.DefaultView...repNews.DataBind(); } 后台代码把绑定的过程定义为一个方法,实现过程如下: 1)首先定义从数据库取数据的 SQL 语句,SQL 语句的意思是:从数据库的新闻表(news)取出按添加日期(adddate...)排序的 11 条记录(top 11),选出字段为:newsid,newsname,adddate; 2)然后调用SqlData类的 dataTable 方法执行 SQL 语句,并把获取到的记录赋给DataTable...repClass.DataBind(); } //绑定新闻 private voidBindNews() { stringstrSQL ="Select top 11 newsid,newsname,adddate
21行左右 将 update_search 方法替换为: public function update_search($typeid ,$id = 0,$data = '',$text = '',$adddate...id),'searchid'); } if($r) { $searchid = $r['searchid']; $this->update(array('data'=>$fulltext_data,'adddate...'=>$adddate,'catid'=>$catid),array('typeid'=>$typeid,'id'=>$id)); } else { $siteid = param::get_cookie...('siteid'); $searchid = $this->insert(array('typeid'=>$typeid,'id'=>$id,'adddate'=>$adddate,'data'=>$...($datas as $id=>$r) { $this->db->update_search($typeid ,$id, $r['fulltextcontent'],$r['title'],$r['adddate
is not null) set @sql = @sql+’ and addDate = ‘+ @addDate + ‘ ‘ if (@name ” and is not null...is not null) and (@name ”) select * from table where addDate = @addDate and name = @name ...else if (@addDate is not null) and (@name =”) select * from table where addDate = @addDate else...addDate or @addDate is null) and (name = @name or @name = ”) 第三种写法是 SELECT * FROM table where... addDate = CASE @addDate IS NULL THEN addDate ELSE @addDate END, name = CASE @name WHEN ” THEN
SQL: insert into b(a, b, c) select d,e,f from b; ◆显示文章、提交人和最后回复时间 SQL: select a.title,a.username,b.adddate...from table a,(select max(adddate) adddate from table where table.title=a.title) b ◆说明:外连接查询(表名1:a
n.Minute()) fmt.Println(n.Second()) fmt.Println(n.Nanosecond()) //获取当前时间一年后,一个月后,一天后 fmt.Println(n.AddDate...(1, 0, 0).String()) fmt.Println(n.AddDate(0, 1, 0).String()) fmt.Println(n.AddDate(0, 0, 1).String())...//获取昨天 fmt.Println(n.AddDate(0, 0, -1).String()) //获取前天 fmt.Println(n.AddDate(0, 0, -2).String())
int m_nYear; public: CDate();//默认构造函数 CDate(int, int, int);//重载构造函数 void Display();//输出日期 void Adddate...CDate::Display() { cout << m_nYear << "年" << m_nMonth << "月" << m_nDay << "日" << endl; } void CDate::Adddate...年月日" << endl; cin >> y >> m >> d; date.Setdate(y, m, d); cout << "当前日期:"; date.Display(); date.Adddate
第7题关于年度、季度SQL统计查询的面试题A表 - 销售数据表,其中adddate是销售时间,company是客户公司,money是销售金额,sales是销售员B表 - 产品销售表,aid对应A表中的id...SELECT YEAR(adddate) AS year, QUARTER(adddate) AS quarter, SUM(money) AS total_salesFROM aWHERE...YEAR(adddate) BETWEEN 2011 AND 2013GROUP BY YEAR(adddate), QUARTER(adddate)ORDER BY YEAR(adddate),...QUARTER(adddate);问题2:请使用SQL语句按如下格式统计2013年销售金额前5位的销售员SELECT sales, SUM(money) AS total_salesFROM...aWHERE YEAR(adddate) = 2013GROUP BY salesORDER BY total_sales DESCLIMIT 5;问题3:请用SQL语句统计出哪个产品线的销售金额最多
) Select ID, Name, Age, AddDate From inserted End ELSE Begin print('年龄应小于150') rollback...BEGIN SET NOCOUNT ON; --这里是先删除后插入,存在一张临时表deleted Insert Into PersonLog(PersonID, Name, Age, AddDate..., UpdateDate) Select ID, Name, Age, AddDate, UpdateDate From inserted END Delete 触发器: 在向目标表中删除数据后,...[Person] AFTER DELETE AS BEGIN SET NOCOUNT ON; Insert Into PersonLog(PersonID, Name, Age, AddDate..., UpdateDate, DeleteDate) Select ID, Name, Age, AddDate, UpdateDate, GETDATE() From deleted END 触发器优点
o[k]).length))); } return fmt; } /** * 拓展Date原型 */ const extDate = () => { Date.prototype.addDate...dateDiff } JS逻辑 首先得根据年月将本月的日历打印出来,使用util.formatDate("yyyy-MM-01", date)获取本月的1号的Data对象,然后计算他是本周的周几,使用Date.addDate...由于每月的日历最多是五个周,所以我们直接打印五个周的时间即可,使用Date.addDate()将日期一天一天累加,并将数据保存即可。...unitObj.color += tmpColor; } innerArr.push(unitObj); start.addDate...}) }, calcVacation: function () { var d = new Date(this.data.termStart); d.addDate
在Go中,时间推算有俩函数,一个是Add,一个是AddDate,分别是+小时和+天数。...AddDate AddDate就牛逼很多了,有三个参数,分别是年,月,日,根据需求加就行了。...main() { //当前时间 nowTime := time.Now() fmt.Println("当前时间:",nowTime) month1 := nowTime.AddDate...(0, 1, 1) fmt.Println("加一个月时间:", month1) month2 := nowTime.AddDate(0, 2, 1) fmt.Println("...其实主要重要的是Add和AddDate,时间 -> 格式化字符串,字符串 -> 时间,这些在平常中使用频率最高。 如果在操作过程中有任何问题,记得下面留言,我们看到会第一时间解决问题。
private long id; private String name; private String description; private String image; private Date addDate...public void setImage(String image) { this.image = image; } public Date getAddDate() { return addDate...; } public void setAddDate(Date addDate) { this.addDate = addDate; } public int getState() {..."AND name LIKE CONCAT('%',#{name},'%')", "", "order by addDate...`news_category` (`id`, `name`, `description`, `image`, `addDate`, `state`) VALUES (null, #{name}, #{description
account:_.inc(money), addrecord:_.push({ money:params.account, adddate...}), spend:_.push({ money:params.account, type:0, adddate...account:_.inc(money), consume:_.push({ money:params.account, adddate...}), spend:_.push({ money:params.account, type:1, adddate...我们绑定一下数据,绑定为我们的充值消费记录字段 [在这里插入图片描述] 对于里边的内容,我们都使用表达式进行绑定 [在这里插入图片描述] app.utils.formatDate($for.id18.adddate
null) t where rn=1 order by sname,pname,position,tname; -- 生成按天分区 select concat('partition p',adddate...('2020-12-31',id)+0,' VALUES LESS THAN (',adddate('2020-12-31',id+1)+0,'),') from nums limit 365;
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